(11b+6)+(b^2-7b+10)=

Solution for (11b+6)+(b^2-7b+10)= equation:

Simplifying
(11b + 6) + (b2 + -7b + 10) = 0

Reorder the terms:
(6 + 11b) + (b2 + -7b + 10) = 0

Remove parenthesis around (6 + 11b)
6 + 11b + (b2 + -7b + 10) = 0

Reorder the terms:
6 + 11b + (10 + -7b + b2) = 0

Remove parenthesis around (10 + -7b + b2)
6 + 11b + 10 + -7b + b2 = 0

Reorder the terms:
6 + 10 + 11b + -7b + b2 = 0

Combine like terms: 6 + 10 = 16
16 + 11b + -7b + b2 = 0

Combine like terms: 11b + -7b = 4b
16 + 4b + b2 = 0

Solving
16 + 4b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-16' to each side of the equation.
16 + 4b + -16 + b2 = 0 + -16

Reorder the terms:
16 + -16 + 4b + b2 = 0 + -16

Combine like terms: 16 + -16 = 0
0 + 4b + b2 = 0 + -16
4b + b2 = 0 + -16

Combine like terms: 0 + -16 = -16
4b + b2 = -16

The b term is 4b.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4b + 4 + b2 = -16 + 4

Reorder the terms:
4 + 4b + b2 = -16 + 4

Combine like terms: -16 + 4 = -12
4 + 4b + b2 = -12

Factor a perfect square on the left side:
(b + 2)(b + 2) = -12

Can't calculate square root of the right side.

The solution to this equation could not be determined.